Web16 mrt. 2024 · Transcript. Ex 6.4, 8 If f(x) = 3x2 + 15x + 5, then the approximate value of f (3.02) is (A) 47.66 (B) 57.66 (C) 67.66 (D) 77.66Let x = 3 and ∆x = 0.02 f’(x) = 6x + 15 Now, ∆y = f’(x) ∆x = (6x + 15) 0.02 Also, ∆y = f (x + ∆x) − f(x) f (x + ∆x) = f (x) + ∆y f (3.02) = 3x2 + 15x + 5 + (6x + 15) (0.02) Since x = 3 f (3.02) = 3(3)2 + 15(3) + 5 + (0.02)[6(3)+15] = … WebSelect all that apply: f(x)=x−52x f(x)=x+3x2−1 f(x)=x5+2x3+5 f(x)=x−69x3 f(x)=x2x−1. Show transcribed image text. Expert Answer. Who are the experts? Experts are tested by Chegg as specialists in their ... If n < m then the horizontal asymptote is the x-axis (y = 0) If n = m then the horizontal asymptote is y = b. If n > m then there is ...
If F(g(x)) =4x^2-8x and F(x) = x^2 -4, then what is g(x)? - Quora
Web12 okt. 2024 · If f(x) = 3x 2 – 2x + 4 and g(x) = 2 – 3x, then find f(x)g(x) for x = -1. Solution: In order to find the multiplication of both the functions, it can be either done by first multiplying the expressions and then putting the value of x or first put the value of x in separate functions and then multiply them. WebLet us start with a function, in this case it is f(x) = x 2, but it could be anything: f(x) = x 2. Here are some simple things we can do to move or scale it on the graph: We can move it up or down by adding a constant to the y-value: g(x) = x 2 + C. Note: to move the line down, we use a negative value for C. C > 0 moves it up; C < 0 moves it down thetford post office
Homework 3.pdf - Math 121—Homework #3 due Friday February...
WebAnswer (1 of 5): Let us solve it by deriving F(g(x)): \frac{d}{dx}F(g(x))=8x-8\quad(1) and from the chain rule: \frac{d}{dx}F(g(x))=F'(g(x))g'(x)=2g(x)g'(x)\quad(2 ... Web8 apr. 2024 · If the range of the function, f (x) = 2 x 3 + 2 x 2 − 4 x x 3 − 3 x 2 + 2 x is R − {α, β, γ}, then (α + β + γ) equals (where R is the set of all real numbers) Updated On Apr … WebIf f (x)=3x-1 f (x) = 3x −1 and g (x)=x^3+2 g(x) = x3 +2, then what is f (g (3)) f (g(3))? Solution One way to evaluate f (g (3)) f (g(3)) is to work from the "inside out". In other words, let's evaluate g (3) g(3) first and then substitute that result into f f to find our answer. Let's evaluate g ( {3}) g(3). thetford pp345